0=-4.9x^2+29.4x+2.5

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Solution for 0=-4.9x^2+29.4x+2.5 equation:



0=-4.9x^2+29.4x+2.5
We move all terms to the left:
0-(-4.9x^2+29.4x+2.5)=0
We add all the numbers together, and all the variables
-(-4.9x^2+29.4x+2.5)=0
We get rid of parentheses
4.9x^2-29.4x-2.5=0
a = 4.9; b = -29.4; c = -2.5;
Δ = b2-4ac
Δ = -29.42-4·4.9·(-2.5)
Δ = 913.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29.4)-\sqrt{913.36}}{2*4.9}=\frac{29.4-\sqrt{913.36}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29.4)+\sqrt{913.36}}{2*4.9}=\frac{29.4+\sqrt{913.36}}{9.8} $

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